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in Technique[技术] by (71.8m points)

一个js的面试题

setTimeout(function () {
  console.log(1);
}, 0);

new Promise(function executor(resolve) {
  console.log(2);
  for (var i = 0; i < 10000; i++) {
    i == 9999 && resolve();
  }
  console.log(3);
}).then(function () {
  console.log(4);
});

console.log(5);

如题,这是我在一个群里面发现的别人的一个面试题,答案已经知道,是23541,但是对其中原理不是太清晰,虽然有些自己的看法,但是觉得走不通,希望能得到各位大神的指点,感谢!


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1 Answer

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by (71.8m points)

首先setTimeout里面的函数会放到下一次event loop中,而promise的异步处理并不会放到下一个event loop,所以最后输出1。先输出2.3这个好理解,而4处在异步调用所以会先输出5,然后才是4


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