http://www.runoob.com/php/php...
使用这个实例操作之后为什么只显示一条数据，如何让符合条件的数据全部显示出来
如，我使用的查询字段是yesterday_str，查询2017-04-18这个数据
怎么样才能把2017-04-18包含这个的全部数据提取出来？
php代码
<?php
$q = isset($_GET["q"]) ? intval($_GET["q"]) : '';
if(empty($q)) {
echo '请选择日期';
exit;
}
$con = mysql_connect('127.0.0.1', 'root', '');
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("rizhifenxi", $con);
mysqli_set_charset($con, "utf8");
#$sql="SELECT * FROM keywords WHERE id = '".$q."'";
$sql="SELECT * FROM keywords WHERE yesterday_str = '".$q."'";
$result = mysql_query($sql);
echo "<table border='10'>
<tr>
<th>日期</th>
<th>关键词</th>
<th>访问次数</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['yesterday_str'] . "</td>";
echo "<td>" . $row['keywords'] . "</td>";
echo "<td>" . $row['count'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysql_close($con);
?>
html代码：
<html>
<head>
<meta charset="utf-8">
<script src="/static/selectuser.js"></script>
</head>
<body>
<form>
Select a User:
<select name="yesterday_str" onchange="showUser(this.value)">
<option value="">选择一个日期:</option>
<option value="1">2017-04-20</option>
<option value="2">2017-04-21</option>
<option value="3">2017-04-22</option>
<option value="4">2017-04-23</option>
</select>
</form>
<p>
<div id="txtHint"><b>yesterday_str info will be listed here.</b></div>
</p>
</body>
</html>
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